Arrangethe elements withthe followingelectronicconfigurationin orderof increasingelectron gainenthalpy (i) 1s^(2)2s^(2) 2p^(5)(ii)1s^(2)2s^(2)2p^(4)(iii)1s^(2)2s^(2)2p^(3)(iv)1s^(2)2s^(2)2p^(6)3s^(2)3p^(4)

Arrangethe elements withthe followingelectronicconfigurationin orderof

1.	Arrangethe elements withthe followingelectronicconfigurationin orderof increasingelectron gainenthalpy (i) 1s^(2)2s^(2) 2p^(5)(ii)1s^(2)2s^(2)2p^(4)(iii)1s^(2)2s^(2)2p^(3)(iv)1s^(2)2s^(2)2p^(6)3s^(2)3p^(4)
Answer» SOLUTION :Out of `F (1S^(2) 2s^(2) 2p^(5)) O (1s^(2) 2s^(2) 2p^(4)) N (1s^(2) 2s^(2) 2p^(3)) ` and `S (1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(4))`, Only N because of itsstableexactly half- filledelectronic configurationhas + veelectrongainenthalpy vhileall othershave-veelectrongainenthalpies .SinceF needsonly onemoreelectron to acquirethe nearestinert gasconfigurationthereforeit hasthe most-veelectrongain enthalpy. Out of O and S, O has lessnegativeelectron gainenthalpythanS because of electron- electron repulsionspresentin itssmallcompact 2p- orbital. Thusoverall order ofincreasingelectrongain enthalpy is : `(i)(IV) lt (iv) lt (ii) lt (iii)`