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Arrangethe followingin decreasingorder oftheirvan derWaalsradii: C1, H , O, R |
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Answer» Solution :The van derWaalsradii increaseas thenumber ofenergyshellsincreasesanddecreasesas thenuclear chargeincreases.SinceH has ONLYONE energyshell.And C1has threethereforethe van beWaalsradiusof H isthesmallestwhile that ofC1 is thelargest . Furtherboth N ANDO havetwo energyshellsbut thenuclearcharge onO (+ 8)is highestthan thatof N (+7)thereforethe van berWaalsradiusradius ofN isbiggerthan thatof O. Thusthe overalldecreasingorder is `C1 GT N gt O gt H` |
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