Arrive at the expression for kinetic energy of particle executing SHM.

1.	Arrive at the expression for kinetic energy of particle executing SHM.
Answer» Solution :`"K.E. of particle "=(1)/(2)m OMEGA^(2)A^(2)-(1)/(2)m omega^(2)X^(2)` `=(1)/(2)m omega^(2)(A^(2)-x^(2))` `"where"x=Acos (omegat+phi)` `"AlsoK.E."=(1)/(2)MOMEGA^(2)(A^(2))(1-cos^(2)(omegat+phi))` `"i.e.,K.E"=(1)/(2)m omega^(2)A^(2)SIN^(2)(omegat+phi)`

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