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Arsenic forms two oxides, one of which contains 65.2 % and the other 75.7% of the element. Hence, equivalent masses of arsenic are in the ratioA. `1:2`B. `3:5`C. `13:15`D. `2:1` |
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Answer» Correct Answer - B In first oxide Mass of arsenic = 65.2 Mass of oxygen = 34.8 `:.` Eq. mass of arsenic `= (65.2)/(34.8)xx8 = 14.99` In second oxide, Mass of arsenic = 75.7 g Mass of oxygen = 24.3 g `:.` Eq. mass of arsenic `= (75.7)/(24.3)xx8` `=24.92` `underset(("oxide I"))("Eq. mass of arsenic")" : "underset(("oxide II"))("Eq. mass of arsenic")` `14.99:24.92` or 3:5 |
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