As per law of mass action, for NH_(4) HS(s) hArrNH_(3)(g) + H_(2) S(g) ratio of rate constants of forward (K_(f)) & backword (K_(b))reactions at equilibrium equals ot

As per law of mass action, for NH_(4) HS(s) hArrNH_(3)(g) + H_(2) S(g)

1.	As per law of mass action, for NH_(4) HS(s) hArrNH_(3)(g) + H_(2) S(g) ratio of rate constants of forward (K_(f)) & backword (K_(b))reactions at equilibrium equals ot
Answer» <P>`[NH_4HS]` `P_(NH_3)+P_(H_2S)` `[H_2S]+[NH_3]` `[NH_3] [H_2S]` SOLUTION :`(K_(f))/(K_(b))=K_(EQ)=[NH_(3)][H_(2)S]`