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As per second law of thermodynamics a process taken place spontaneously if and only if the entropy of the universe increases due to the process. Change in entropy is given by Delta S = (Q_(rev))/(T) What is the change in entropy of the universe due to the following reaction occuring at 27^(@)C ? A + 2B rarr C + 2D, Delta H = +1.8 kJ mol^(-1) Molar entropy values of A, B, C and D are 1,2,3 and 4 JK^(-1) mol^(-1) respectively. |
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Answer» 0 `= (Sigma S_(P)- Sigma S_(R )) + ((-Delta H_("system"))/(T))` `= (2(4) + 3-2(2)-1) + ((-1.8 xx 10^(3))/(300))` `= 6-6 = 0` |
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