InterviewSolution
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InterviewSolution
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As shown in figure, a metal rod completes the circuit. The circuit area is perpendicular to a magnetic field with `B = 0.15 T`. If the resistance of the total circuit is `3 Omega`, how large a force is needed to move the rod as indicated with a constant speed of 2 m/s? A. `3.75xx10^(-3)N`B. `3.75xx10^(-2)N`C. `3.75xx10^(2)N`D. `3.75xx10^(-4)` |
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Answer» Correct Answer - A Induced current in the circuit `i=(Bvl)/(R )` Magneticforceactingonthewire `F_(m)=bil=B(Bvl)/(R ))l` `impliesF_(m)=(B^(2)vl^(2))/(R )` External force needed to move the rod with constant velocity `(F_(m))=(B^(2)vl^(2))/(R )=((0.15)^(2)xx(2)xx(0.5)^(2))/(3)` `=3.75xx10^(-3)N` |
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