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As shown in figure, a metal rod completes the circuit. The circuit area is perpendicular to a magnetic field with `B = 0.15 T`. If the resistance of the total circuit is `3 Omega`, how large a force is needed to move the rod as indicated with a constant speed of 2 m/s? A. `3.75xx10^(-3)N`B. `2.75xx10^(-3)N`C. `6.57xx10^(-4)N`D. `4.36xx10^(-4)N` |
Answer» Correct Answer - A Given, B = 0.15 T, l = `50xx10^(-2)` cm and v = 2 `ms^(-2)` `therefore` emf , e = Bvl `e=0.15xx2xx50xx10^(-2)=0.15` Current, `i=(e)/(R)=(0.15)/(3)=5xx10^(-2)` Force, F = Bil = `0.15xx5xx10^(-2)xx50xx10^(-2)` `=3.75xx10^(-3)N` |
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