As shown in figure lower portion of the manometer tube contains fluid of density rho_(1) and the upper part contains fluid of density rho_(2)(rho_(1)gtrho_(2)) . Ifpressures on the top of these two arms are P_(1)andP_(2), calculate pressure differnce (P_(1)-P_(2)).

As shown in figure lower portion of the manometer tube contains fluid

1.	As shown in figure lower portion of the manometer tube contains fluid of density rho_(1) and the upper part contains fluid of density rho_(2)(rho_(1)gtrho_(2)) . Ifpressures on the top of these two arms are P_(1)andP_(2), calculate pressure differnce (P_(1)-P_(2)).
Answer» Solution :Consider POINTS A and B , as SHOWN in the diagram , at EQUAL height from bottom.For these points , `P_(A)=P_(B)` `thereforeP_(1)+(h+x)rho_(2)g=xrho_(2)g+hrho_(1)g+P_(2)` `thereforeP_(1)-P_(2)=xrho_(2)g+hrho_(1)g-hrho_(2)g-xrho_(2)g` `thereforeP_(1)-P_(2)=(rho_()-rho_(2))hg`