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As shown in figure process AB is isobaric, BC is adiabasic CD is isochoric and DA is isothermal, through which n-moles of monoatomic gas undergo a cyclic process. The max & min temperature in the cycle are `4T_(0)` and `T_(0)` respectively.A. `T_(B)` is greater than `T_(D)`B. Heat is released by gas in the process CDC. Heat is supplied to the gas in the process ABD. `T_(C)` is greater than `T_(A)` |
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Answer» Correct Answer - A::B::C::D DA is isothermal `becauseT_(D)=T_(A)` `TalphaPV` from graph `(PV)_(C)gt(PV)_(D)` BC is adiabatic expansion so, `T_(B)gtT_(C)` so `T_(B)gtT_(D)` and `T_(B)gtT_(A)` maximum temperature at B or C and minimum temperature at D or A. `T_(B)=4T_(D)` `T_(D)=T_(A)=T_(B)` IN process `CD:DeltaW=0,DeltaQ=DeltaU` pressure is decreasing, volume is constant. Temperature and intenal energy will decrease. `DeltaQ=-ve`, heat is released in CD. In `AB,DeltaQ=nC_(P)DeltaT` Volume is increasing and pressure is constant, temperature will increase `DeltaQ` is positive so, heat is supplied to the gas in process AB. |
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