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As shown in the figure, charges `+q and -q` are placed at the vertices `B` and `C` of an isoscles triangle. The potential at the vertex `A` is A. `(1)/(4pi epsilon_(0)).(2q)/(sqrt(a^(2)+b^(2)))`B. zeroC. `(1)/(4pi epsilon_(0)).(q)/(sqrt(a^(2)+b^(2)))`D. `(1)/(4pi epsilon_(0)).(-q)/(sqrt(a^(2)+b^(2)))` |
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Answer» Correct Answer - B |
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