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As student performs an experiment for determine of `g[=(4pi^(2)L)/(T^(2))]. L approx 1m`, and has commits an error of `Delta L` for `T` he tajes the teime of `n` osciollations wityh the stop watch of least count `Delta T`. For which of the following data the measurement of `g` will be most accurate?A. `Delta L = 0.5, DeltaT = 0.1n = 20`B. `Delta L = 0.5, DeltaT = 0.1n = 50`C. `Delta L = 0.5, DeltaT = 0.01n = 20`D. `Delta L = 0.5, DeltaT = 0.05n = 50` |
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Answer» Correct Answer - D `(Delta g)/(g) = (Delta l)/(l) + 2(Delta T)/(T)` (`Delta l` and `DeltaT` are least and the number of readings are maximum) |
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