As you have learnt in the text a geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of this satellite ? (Take the potential energy at infinity to be zero). Mass of the earth6.0xx 10^(24(kg) , Radius = 6400 km .

As you have learnt in the text a geostationary satellite orbits the ea

1.	As you have learnt in the text a geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of this satellite ? (Take the potential energy at infinity to be zero). Mass of the earth6.0xx 10^(24(kg) , Radius = 6400 km .
Answer» SOLUTION :`implies` Mass of the earth `M_(E) 6.0 XX 10^(24) kg,` Radius of earth `R_(E) = 6400 km = 6.4 xx 10^(7)m` DISTANCE of geo stationary satellite from the surface of earth h `= 3600 km = 3.6 xx 10^(7) m` Gravitational potential due to earth.s gravity at height h, `phi= (-GM_E)/(R_(E)+h)` `=-(6.67 xx10^(-11)xx6xx10^(24))/(6.4 xx10^(6)+36 xx 10^(6))` `=-(40.02xx 10^(13))/(4.24xx10^(7))` `=-9.43 xx10^(6)Jkg`