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AskGin GUJCET/Board ExamFreezing point of urea solution is -0.6° C.How much urea is required to be dissolved in3 kg water?[M(urea) = 60 g mol!, K = 1.5°C Kg mol |
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Answer» Answer: Amount of UREA = 1.02g no. of mole = 1.02/60 MOLAR mass of urea (NH 2
CONH 2
)=60 Molality = 60 1.02
× 98.5 1000
=0.17259 ΔT f
=K f
m⇒0.211=k f
×0.1759 ...(i) LET molar mass of unknown COMPOUND = M ΔT f
=k f
m ΔT f
=k d
× M 1.60
. 80.6 1000
0.34=k f
× M 19.85
...(ii) divide equation (i) by (ii) 0.34 0.211
= 19.85 0.1759
×M M= 0.34×17.59 0.211×19.85
=70gm |
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