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AskGin GUJCET/Board ExamFreezing point of urea solution is -0.6° C.How much urea is required to be dissolved in3 kg water?[M(urea) = 60 g mol!, K = 1.5°C Kg mol​

Answer»

Answer:

Amount of UREA = 1.02g

no. of mole = 1.02/60

MOLAR mass of urea (NH

2

CONH

2

)=60

Molality =

60

1.02

×

98.5

1000

=0.17259

ΔT

f

=K

f

m⇒0.211=k

f

×0.1759 ...(i)

LET molar mass of unknown COMPOUND = M

ΔT

f

=k

f

m

ΔT

f

=k

d

×

M

1.60

.

80.6

1000

0.34=k

f

×

M

19.85

...(ii)

divide equation (i) by (ii)

0.34

0.211

=

19.85

0.1759

×M

M=

0.34×17.59

0.211×19.85

=70gm



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