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Assertion (A): All the carbon atoms in H_(2)C = C = CH_(2) are sp^(2)-hybridised Reason (R ): In this molecule all the carbon atoms are attached to each other by double bonds. |
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Answer» Both (A ) and (R ) are correct and (R ) is the correct explanation of (A) If four `SIGMA`-bond with C then it is `sp^(3)` carbon. If three `sigma`-bond with C then it is `sp^(2)` carbon. And if two `sigma`-bond with C then it is sp carbon. So, Assertion (A) is not correct Because (R ) Reason is correct. In these example all carbon are attached by DOUBLE bond with each other `underset("Between double bond")(overset(1)(C )H_(2) underset(underset(C_(1)-C_(2))(darr))(=) overset(2)(C )H underset(underset(underset(C_(2) and C_(3))("Double bond between"))(darr))(=) overset(3)(C )H_(2)` |
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