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Assertion : Bond order of F_(2) is one . Reaso : ABMO electrons are 2 unit less than BMO. |
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Answer» ASSERTION (A) and Reason (R) both are correct and (R) gives correct explanation. `F_(2) (9 + 9 = 18)` `(sigma_(1s))^(2) lt (sigma_(1s)^(**))^(2) lt (sigma_(2s))^(2) lt (sigma_(2s)^(**))^(2) lt (sigma_(2pz)^(**))^(2) lt (pi_(2PX))^(2)= (pi_(2py))^(2) lt (pi_(2p_(x))^(**))^(2) (pi_(2p_(y)))^(2)` `{:("Electron of BMO =10"),("Electron of ABMO" = 8):}} ` so , BO = `(1)/(2) (N_(b) - N_(a) ) = (1)/(2) (10 - 8) = 1 ` |
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