1.

Assertion. If the length of the unit cell of LiCl having NaCl structure is 5.14 Å , the ionic radius ofCl^(-) ion is 1.82 Å.Reason . Anion-anion contact is retained in LiCl structurebeacause anions constitute the lattice.

Answer»


SOLUTION :If anion -anion contact is retained , then as shown in the adjoining fig,

Interionic distance of LICL = `a/2`
` ( 5.14 Å)/2 = 2.57Å `
`BC = sqrt(AB^(2) + AC^(2)) = sqrt((2.57)^(2) + ( 2.57)^(2))`= 3.63 Å
Radius of ` Cl^(-) "ION" = 1/2 BC = 1/2 xx 3.63= 1.81 Å`
Hecne, R is the correct explanation of A.


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