Assertion : If three identical bulbs are connected in series as shown in figure then on closing the switchs. Bulb `C` short circuited and hence illumination of bulbs `A` and `B` decreases. Reason : Voltage on `A` and `B` decreases A. both A and B will glow more brightlyB. both A and B will glow less brightly than beforeC. A will glow less brightly and B more brightlyD. None of the bulbs will glow

Assertion : If three identical bulbs are connected in series as shown

1.	Assertion : If three identical bulbs are connected in series as shown in figure then on closing the switchs. Bulb `C` short circuited and hence illumination of bulbs `A` and `B` decreases. Reason : Voltage on `A` and `B` decreases A. both A and B will glow more brightlyB. both A and B will glow less brightly than beforeC. A will glow less brightly and B more brightlyD. None of the bulbs will glow
Answer» Correct Answer - C Bulbs B and C are connected in parallel. Suppose, voltage across A and B is same. If bulb C is fused, bulb B will work `P_(B)=(V^(2))/(R_(B))impliesP_(A)=(V^(2))/(R_(A))` `R=(R_(B)R_(C))/(R_(B)+R_(C))` `because " " R_(B) lt R_(A) therefore P_(B) gt P_(A)`

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