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Assertion: The first ionisation energy of `Be` is greater than that of `B`. Reason: 2p-orbital is lower in energy than 2s-orbital.A. Statement-I is true, Statement-II is true ,Statement -II is the correct explanation for Statement-IB. Statement-I is true ,Statement -II is true, Statement -II is not the correct explanation for statement -IIC. Statement-I is true. Statement -II is false.D. Statement-I is false. Statement -II is true. |
Answer» Correct Answer - C Statement II is incorrect. The first ionisation energy of Be is greater than that of B because of its relatively stable electronic configuration. `Be=2s^(2), B=2s^(2) 2p^(2)` It is easier to remove electron from `2p` orbitals than `2s` orbitals since `2s` is much more penetrated towards nucleus. Hence `IE_(1)` of `Be gt IE_(1)` of B. Therefore, `2p`-orbital has rather higher energy than `2s`. |
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