Assertion.When 1.0 mol of NaCl is doped with 10^(-3) "mol " SrCl^(2) . The number of cationic of cationic sites remaining vacant is 10^(-3) . Each SrCl_(2) unit produces two cation vacancies.

Assertion.When 1.0 mol of NaCl is doped with 10^(-3) "mol " SrCl^(2) .

1.	Assertion.When 1.0 mol of NaCl is doped with 10^(-3) "mol " SrCl^(2) . The number of cationic of cationic sites remaining vacant is 10^(-3) . Each SrCl_(2) unit produces two cation vacancies.
Answer» SOLUTION :Correct A. As each `SrCl_(2)` unit creates ONE CATION vacancy, number of cation vacancies will be ` 10^(-3) " MOL" = 10^(-3) xx ( 6.02 xx 10^(23)) = 6.02 xx 10^(20)` Correct R. Each `SrCl_(2)` produces one cation vacancy .