1.

Assertion. When 1.0 mol of NaCl is doped with `10^(-3) "mol " SrCl^(2)` . The number of cationic of cationic sites remaining vacant is `10^(-3)` . Each `SrCl_(2)` unit produces two cation vacancies.

Answer» Correct Answer - a
Correct A. As each `SrCl_(2)` unit creates one cation vacancy, number of cation vacancies will be ` 10^(-3) " mol" = 10^(-3) xx ( 6.02 xx 10^(23)) = 6.02 xx 10^(20)`
Correct R. Each `SrCl_(2)` produces one cation vacancy .


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