1.

Assign oxidation number to the underlined elements in each of the following species : NaH_(2)ul(P)O_(4)

Answer»

Solution :LET the oxidation number of P be x. Writing the oxidation NUMBERS of all elements present, we have
`overset(+1+1)(NaH_(2))overset(x-2)(PO_(4))`
The sum of oxidation numbers of all atoms in a NEUTRAL molecule is zero. Hence,
`(+1)+[(+1)xx2]+(x)+[(-2)xx4]=0`
or `x=+8-3=+5`
Thus, the oxidation number of P in `NaH_(2)PO_(4)` is +5.


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