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Assign oxidation number to the underlined elements in each of the following species : NaHul(S)O_(4) |
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Answer» Solution :`overset(+1)(NA)overset(+1)(H)overset(X)(S)overset(-2)(O_(4))` `(+1)+(+1)+(x)+[(-2)xx4]=` or `x=+8-2=+6` Therefore, the OXIDATION number of S in `NaHSO_(4)` is + 6. |
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