Saved Bookmarks
| 1. |
Assign oxidation number to the underlined elements in each of the following species : Naul(B)H_(4) |
|
Answer» Solution :In `NaBH_(4)`, H is present as `H^(-)` ion because it is a hydride. THEREFORE, oxidation NUMBER of H in it is -1. `OVERSET(+1)(NA)overset(x)(B)overset(-1)(H_(4))` `(+1)+(x)+[(-1)xx4]=0` or `x=+4-1=+3` `:.` The oxidation number of B in `NaBH_(4)` is +3. |
|