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Assume that if the earth were made of lead of relative density 11.3, then what would be the value of acceleration due to gravity on the earth surface ?

Answer» <html><body><p></p>Solution :Since, <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> of earth can be given as <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>=` Relative density `xx` density of water `=11.3 xx 10^(3) "kgm"^(-3)` <br/> `:.` Acceleration due to <a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a> on the earth's surface, <br/> `g=(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(R^(2))=(G)/(R^(2)).(4)/(3)piR^(3).rho` <br/> `=(4)/(3)xx(22)/(7)xx6.67xx10^(-11)xx6.4 xx10^(6)xx11.2xx10^(3)` <br/> `=22.21 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-2)`</body></html>


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