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Assume that the temperature remains essentially constant in the upper parts of the atmosphere. The atmospheric pressure varies with height as. (the mean molecular weight of air is M, where `P_(0)=` atmospheric pressure at ground reference)A. `P_()e^((-3Mgh)/(2RT))`B. `P_(0)e^((-Mgh)/(2RT))`C. `P_(0)e^((-3Mgh)/(RT))`D. `P_(0)e^((Mgh)/(RT))` |
Answer» Correct Answer - D Since pressure decreased with height `dp=pgdh` Consider a small volume `deltaV` of air of mass `Deltam` `P Delta V=((Deltam)/(M))RT` `P=(Deltam)/(Deltav)(RT)/(M)rArrP=(rhoRT)/(M)rArrrho=(PM)/(RT)` `therefore dp=(PM)/(RT)g dh` `int_(P_(0))^(P)(dP)/(P)=-(Mg)/(RT)int_(0)^(h)dh` In `((P)/(P_(0)))=-(-Mgh)/(RT)` `P=P_(0)e^((-Mgh)/(RT))` |
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