Assuming all the surface to be frictionless. The smaller block m ismoving horizontally with acceleration a and vertically downwards with acceleration a. Then magnitude of net acceleration of smaller block m with respect to ground

Assuming all the surface to be frictionless. The smaller block m ismov

1.	Assuming all the surface to be frictionless. The smaller block m ismoving horizontally with acceleration a and vertically downwards with acceleration a. Then magnitude of net acceleration of smaller block m with respect to ground
Answer» `(2sqrt5mg)/((5m+M))` `(2MG)/((5m+M))` `7sqrt5g` none of these Solution :FREE BODY diagram for m For m, `mg-T=m2aâ€¦(i)` `N=ma â€¦(ii)` Free body diagram for M For M, `2T-N=Maâ€¦(iii)` on solving, `a=(2mg)/((M+5m))` Net ACCELERATION of m, `a_(m)=sqrt(4a^(2)+a^(2))=sqrt5a=(2sqrt5mg)/((5m+M))`