Assuming that air at STP contained 80% by volume of nitrogen, the volumeof air at STP that contains 4.8xx10^(23) molecules of notrogen is

Assuming that air at STP contained 80% by volume of nitrogen, the volu

1.	Assuming that air at STP contained 80% by volume of nitrogen, the volumeof air at STP that contains 4.8xx10^(23) molecules of notrogen is
Answer» 18 L 44.8 L 22.4 L 11.2 L Solution :22.4 litres AIR - STP - `6.023xx10^(23)` molecules `therefore` Nitrogen molecules `=(80)/(100)xx6.023xx10^(23)` `~~4.8xx10^(23)` molecules