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Assuming the earth to be a homogeneous sphere of radius `R`, its density in terms of `G` (constant of gravitation) and `g` (acceleration due to gravity on the surface of the earth)A. `3g//(4piRG)`B. `4pig//(3RG)`C. `4piRg//(3G)`D. `4piRG//(3g)` |
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Answer» Correct Answer - A `g=(GM)/(R^(2))` or `g/(4/3piR)=(GM)/(4/3piR^(3))` or `(3g)/(4piRG)=rho` |
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