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Assuming the validity of the operations on the r.h.s. find dy/dt y = sqrt[[sin x + sqrt{{sin x + sqrt((sin x + ........)}])}] |
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Answer» SOLUTION :`y = {sqrt [SIN + sqrt {sin x +1........]}}` sqrt(sin x + y) IMPLIES y^2 + sin x + y implies 2Y (dy)/(DX) = cos x + dy/dx implies (2y-1) dy/dx = cos x implies dy/dx = cos x/(2y-1)` |
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