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Assuming Young.s modulus of aluminium to be 7 xx 10 N//m^(2) find energy stored in a rod of cross section 10^(-4)m^(-2) and 0.1 m long when com-pressed by a load of 10 kg. |
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Answer» SOLUTION :ENERGY stored `=(1)/(2)` (stretching force) (elongation) `=(1)/(2)(10xx9.8)` (compression) compression `=Deltal=(Mgl)/(AY)=(10xx9.8xx0.1)/(10^(-4)xx7xx10^(10))=10^(-6)xx1.4` `:.` Energy soted `=(1)/(2)(10xx9.8)(1.4xx10^(-6))=6.86xx10^(-5)` Joule |
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