1.

Astring of length 2L, obeying hooke's law, is stretched so that its extension is L. the sped of the tansverse wave travelling on the string is v. if the sting is further on the string will be

Answer»

`(1)/sqrt(2)V`
`sqrt(2)v`
`(1)/(2)v`
`2V`

SOLUTION :`v=sqrt((T)/(mu))`
T can be CALCULATE by using HOOKE's law and on stretching `mu` ALSO changes.


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