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    				| 1. | At `0^(@)C,DeltaH_(fus)^(@)=6kJ //mol`, change of entropy for freezing of one mole of ice will be `:`A. `oo`B. 0C. `21.98J//mol-K`D. `13.6J//mol-K` | 
| Answer» Correct Answer - C `DeltaS=(DeltaH_(f)^(@))/(T_(f))=(6000)/(273)=21.97J//moll-K` | |