The enthalpy of combustion of graphite is 393.4 kJ. Calculate(a) The a

1.	The enthalpy of combustion of graphite is 393.4 kJ. Calculate(a) The amount of graphite needed to produce 196.7 KJ of heat.(b) The number of moles of CO2 formed when 196.7 KJ of heat is produced.(c) The volume of oxygen required at S.T.P. to from 24.0 g of graphite in this process.
Answer» We are given (i) C(graphite) + O₂(g) → CO₂(g); ΔH=-393.4KJ (a) From the above equation, we know that 393.4 KJ of heat is produced by 12 g of graphite. 196.7 kj of heat is produced by 12/393.4 x 196.7= 6 g of graphite (b) From equation (i) we can say that Production of 393.4 KJ of heat is accompanied by the formation of 1 mole of CO₂. Production of 196.7 KJ of heat is accompanied by the formation of 0.5 mole of CO₂. (C) Volume of oxygen required at S.T.P to burn 12 g of graphite = 22.4 litres. Volume of oxygen required at S.T.P to burn 24 of graphite = 22.4 X 2 = 44.8 litres.

The enthalpy of combustion of graphite is 393.4 kJ. Calculate(a) The amount of graphite needed to produce 196.7 KJ of heat.(b) The number of moles of CO2 formed when 196.7 KJ of heat is produced.(c) The volume of oxygen required at S.T.P. to from 24.0 g of graphite in this process.

Answer»

We are given

(i) C(graphite) + O₂(g) → CO₂(g); ΔH=-393.4KJ

(a) From the above equation, we know that 393.4 KJ of heat is produced by 12 g of graphite.

196.7 kj of heat is produced by

12/393.4 x 196.7= 6 g of graphite

(b) From equation (i) we can say that

Production of 393.4 KJ of heat is accompanied by the formation of 1 mole of CO₂.

Production of 196.7 KJ of heat is accompanied by the formation of 0.5 mole of CO₂.

Volume of oxygen required at S.T.P to burn 24 of graphite = 22.4 X 2 = 44.8 litres.

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