At 0^(@)C ice and water are in equilibrium and Delta H= 6.0KJ " then " Delta S will be

At 0^(@)C ice and water are in equilibrium and Delta H= 6.0KJ " then "

1.	At 0^(@)C ice and water are in equilibrium and Delta H= 6.0KJ " then " Delta S will be
Answer» `22 JK^(-1) MOL^(-1)` `35 JK^(-1) mol^(-1)` `48 JK^(-1) mol^(-1)` `100 JK^(-1) mol^(-1)` Solution :`DELTA S = (Delta H)/(T) = (6000)/(273) = 22`