At 0^(@)C , ice and water are in equilibrium and DeltaS and DeltaG for the conversion of ice to liquid water is

At 0^(@)C , ice and water are in equilibrium and DeltaS and DeltaG for

1.	At 0^(@)C , ice and water are in equilibrium and DeltaS and DeltaG for the conversion of ice to liquid water is
Answer» `0,21.98JK^(-1)MOL^(-1)` `-ve` , ZERO `+ve,21.98JKk^(-1)mol^(-1)` All of these Solution :Since the given process is in EQUILIBRIUM, i.e., `DeltaG=0` `DeltaG=DELTAH-TDeltaS` or, `0=DeltaH-TDeltaS` or `DeltaH=TDeltaS` or, `Delta=(DeltaH)/(T)=(6)/(273)xx10^(3)` `JK^(-1)mol^(-1)=21.98JK^(-1)mol^(-1)`