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At 0^(@)C, the density of a certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide ? |
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Answer» Solution :Relation between DENSITY pressure and molecular mass according to eq. `M=(dRT)/(p)` `d=(pM)/(RT)` `THEREFORE M=(dRT)/(p)` where, T = 0.2 R = GAS constant d = density Thus, dRT = Constant No. (K) `therefore M =(K)/(p)` and `M PROP (1)/(p)` Thus, `M_(1)p_(1)=M_(2)p_(2)` where, `M_(1)=` molecular mass of OXIDE = (?) `M_(2)=` molecular mass of `N_(2)=28 g mol^(-1)` `p_(1)=` pressure of oxide = 2 bar `p_(2)=` pressure of `N_(2)=5` bar Thus, `M_(1)xx2` bar `= 28xx5` `therefore M_(1)=(28xx5)/(2)=70 g mol^(-1)` |
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