1.

At 0^(@)C, the density of a certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide?

Answer»

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SOLUTION :For nitrogen,
`d=(M*P)/(RT)`
`(28xx5)/(Rxx273) ( :." mol. mass of " N_2 = 28` )
For the gaseous OXIDE,
`d= (M*P)/(RT) = (Mxx2)/(Rxx273)`
Since, the two densities are EQUAL
`:. "" (28xx5)/(Rxx273)= (Rxx2)/(Rxx273)`
or `M = (28xx5)/2 = 70g mol^(-1)`


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