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At 0^(@)C, the density of a certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide? |
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Answer» <P> SOLUTION :For nitrogen,`d=(M*P)/(RT)` `(28xx5)/(Rxx273) ( :." mol. mass of " N_2 = 28` ) For the gaseous OXIDE, `d= (M*P)/(RT) = (Mxx2)/(Rxx273)` Since, the two densities are EQUAL `:. "" (28xx5)/(Rxx273)= (Rxx2)/(Rxx273)` or `M = (28xx5)/2 = 70g mol^(-1)` |
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