InterviewSolution
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InterviewSolution
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At `0^(@)C` the density of a gaseous oxide at 2 bar is same as that of nitrogen at 5 bar What is the molecular mass of the oxide ? . |
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Answer» The density `(rho)` of a gas `= PM//RT` Here R and T are the constants for the gases For nitrogen, `P = 5 "bar", M = 28 g mol^(-1)` `:. rho_(N_(2)) = (PM)/(RT) = ((5 "bar") xx (28 g mol^(-1)))/(R xx T)` For gaseous oxide, `P = 2 "bar" , M = ?` `:. rho_("oxide") = (PM)/(RT) = ((2 "bar") xx M)/(R xx T)` According to available data , `rho_(N_(2)) = rho _("oxide")` or `(5 "bar") xx (28 g mol^(-1)) = (2 "bar") xx M` `:. M = ((5 "bar") xx (28 g mol^(-1)))/((2 "bar")) = 70 g mol^(-1)`. |
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