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At 0°C the density of a certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide? |
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Answer» P = ρ{RT}/{M} If M is the molar mass of the gaseous oxide, we can write 2 bar = ρ{RT}/{M} and for nitrogen 5 bar = ρ{RT}/{28 g/mol} From these equation, we can write {5 bar}/{2 bar} = {M}/{28 g.mol} or, M = {5 bar}/{2 bar} x 28 g mol-1 = 70 g mol-1 |
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