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At `100^(@)C` and 1 atm, if the density of the liquid water is `1.0 g cm^(-3)` and that of water vapour is `0.0006 g cm^(-3)` , then the volume occupied by water molecules in `1 L` steam at this temperature isA. `6 cm^(3)`B. `60 cm^(3)`C. `0.6 cm^(3)`D. `0.06 cm^(3)` |
Answer» Correct Answer - D Mass of water in `1 L` steam `= 1000 xx 0.00006 g` `= 0.06 g` Volume of `0.06 g` water `= (0.06)/(1 g cm^(-3)) = 0.06 cm^(3)` |
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