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At `100^(@)C` and `1 atm`, if the density of the liquid water is `1.0 g cm^(-3)` and that of water vapour is `0.0006 g cm^(-3)`, then the volume occupied by water molecules in `1 L` of steam at this temperature isA. (a)`6 cm^(3)`B. (b)`60 cm^(3)`C. (c )`0.6 cm^(3)`D. (d)`0.06 cm^(3)` |
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Answer» Correct Answer - D For water vapour, `P=0.0006 g c c^(-1)` `:. 0.0006="Mass"/"Volume"="Mass"/1000` Mass`=1000xx0.0006=0.6` g`:. 0.0006="Mass"/"Volume"="Mass"/1000` Mass`=1000xx0.0006=0.6` g the density of liquid water is `1 g c c^(-1)` So, the volume occupied by water is `"Mass"/"Density"=0.6/1=0.6 c c` |
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