InterviewSolution
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InterviewSolution
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At 100°C, Kw100°C will be10-12, pH of pure water at(2) 6.0(4) 12.0(3) 8.0 |
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Answer» Kwof water = [H+][OH-]10-12=[H+][OH-]at 100oC Let us assume the concentration of H+ = x Since each water molecules dissociates into one proton and one hydroxide ion.i.e. the quantity or the concentration of these two ions will be equal in water.[H+] = [OH-] Therefore10-12= x.x10-12= x2x = 10-6 [H+] = [OH-] =10-6 pH = - log[H+] = - log10-6= 6 log 10 = 6 |
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