InterviewSolution
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InterviewSolution
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At `1400 K, K_( c) = 2.5 xx 10^(-3)` for the reaction `CH_(4)(g)+2H_(2)S(g)hArrCS_(2)(g)+4H_(2)(g)` A ` 10 L` reaction vessel at `1400 K` contains `2.0 mol` of `CH_(4)`, `3.0 mol` of `CS_(2)`, `3.0 mol` of `H_(2)S`. In which direction does the reaction proceed to reach equilibrium?A. ForwardB. BackwardC. May be forward or backwardD. Reaction is in equilibrium |
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Answer» Correct Answer - B `CH_(4)(g)+2H_(2)S(g)overset(K)(hArr)CS_(2)(g)+4H_(2)(g)` or `K=([CS_(2)][H_(2)]^(2))/([CH_(4)][H_(2)S]^(2)) ...(i), [CS_(2)]=(3/10),[H_(2)]=(3/10),[CH_(4)]=(2/10)` and `[H_(2)S]=(4/10)` Substituting the cocentration values in equation (i). `K=((3/10)(3/10)^(4))/((2/10)(4/10))=3^(5)/10^(5)xx10^(3)/(2xx4^(4))xx243/3200=0.075` Therefore, `K gt 2.5xx10^(-3)` (given). Hence, the reaction will proceed in backward direction. |
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