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At 2 atm pressure the value of `x/m` will be :(log 2=0.3010) |
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Answer» Correct Answer - 4 `x/m=K P^(1//n)` `"log"x/m="log"K+1/n"log"P` `:. K=2 & 1/n=1 or n=1` On putting in `eq^n(1)` `x/m=2xx2=4` |
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