InterviewSolution
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InterviewSolution
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At `20^(@)C`, the osmotic pressure of urea solution is `400 mm`. The solution is diluted and the temperature is raised to `35^(@)C`, when the osmotic pressureis found to be `105.3 mm`. Determine extent of dilution. |
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Answer» For initial solution, `pi = (400)/(760)atm, T = 293 K` `(400)/(760) xx V_(1) = n xx S xx 293` …(i) After dilution, let volume becomes `V_(2)` and temperature is raised to `35^(@)C`, i.e., `308 K`. and `pi = (105.3)/(760)atm` `(105.3)/(760) xx V_(2) = n xx S xx 308` ...(2) By eqs. (1) and (2), we get `(V_(1))/(V_(2)) = (293)/(308) xx (105.3)/(400)` `(V_(1))/(V_(2)) = (1)/(4)` or `V_(2) = 4V_(1)` i.e., Solution was diluted to `4` times. |
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