At `25^(@)C`, a solution containing `0.2 g` of polyisobutylene in `100 mL` of benzene developed a rise of `2.4 mm` at osmotic equilibrium. Calculate the molecular weight of polyisobutylene if the density of solution is `0.88 g// mL`.

At `25^(@)C`, a solution containing `0.2 g` of polyisobutylene in `100

1.	At `25^(@)C`, a solution containing `0.2 g` of polyisobutylene in `100 mL` of benzene developed a rise of `2.4 mm` at osmotic equilibrium. Calculate the molecular weight of polyisobutylene if the density of solution is `0.88 g// mL`.
Answer» Height developed `= 2.4 mm` Osmotic pressure `= h.d.g` `= (2.4)/(10) xx 0.88 xx 981` `= 207.187 "dyne" cm^(-2)` Now `piV = nST` `207.187 xx 100 = (0.2)/(m) xx 8.314 xx 10^(7) xx 298` (`R` in erg, `V` in `mL`, using `CGS` system) `m = 2.39 xx 10^(5)`

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At `25^(@)C`, a solution containing `0.2 g` of polyisobutylene in `100 mL` of benzene developed a rise of `2.4 mm` at osmotic equilibrium. Calculate the molecular weight of polyisobutylene if the density of solution is `0.88 g// mL`.

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