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At `25^(@)C` aqueous solution of glucose (molecular weight `= 180 g mol^(-1)`) is isotonic with a 2% aqueous solution containing an unknown solute. What is the molecular weight of the unknown soluteA. 60B. 80C. 72D. 63 |
Answer» Correct Answer - C `pi_("glucose")=pi_("unknown solute")` `therefore (m_(1))/(M_(1))=(m_(2))/(M_(2))` or `(5)/(180)=(2)/(M_(2))rArr M_(2)=72`. |
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