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At `25^(@)`C the equilibrium constant K,and `K_(2)` of two reaction are `2NH_(3)hArrN_(2)+3H_(2) ,K_(1)` `(1)/(2)N_(2)+(3)/(2)H_(2)hArrNH_(3),K_(2)` The relation `b//w` two equilibrium constant is :-A. `K_(1)=K_(2)`B. `K_(2)=(1)/(K_(1)^(2)`C. `K_(1)=(1)/(K_(2)^(2)`D. `K_(1)=(1)/(K_(2)` |
| Answer» Correct Answer - C | |