At `25^(@)C`, the resistance of `0.01 N NaCl` solution is `200 ohm` . If cell constant of the conductivity cell is unity, then the equivalent conductance of the solution is:

At `25^(@)C`, the resistance of `0.01 N NaCl` solution is `200 ohm` .

1.	At `25^(@)C`, the resistance of `0.01 N NaCl` solution is `200 ohm` . If cell constant of the conductivity cell is unity, then the equivalent conductance of the solution is:
Answer» Correct Answer - `500 ohm^(-1)` Step I. Calculation of specific conductance Specific conductance (k)`=("cell constant")/("R")=((1" cm"^(-1)))/((200 ohm))=0.005" ohm"^(-1) cm^(-1)`. Step II. Calculation of equivalent conductance of solution `Lambda_(E)=(1000xxk)/(N)=((1000 cm^(3))xx(0.005" ohm"^(-1)cm^(-1)))/((0.01"g eq"))=500" ohm"^(-1)cm^(2)("g eq")^(-1)`.

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At `25^(@)C`, the resistance of `0.01 N NaCl` solution is `200 ohm` . If cell constant of the conductivity cell is unity, then the equivalent conductance of the solution is:

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